PDO准备带问号的功能不适用于数字 [英] PDO prepare with question marks doesn't work with numbers
本文介绍了PDO准备带问号的功能不适用于数字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这个:
$pdo = new PDO('mysql:host=localhost;dbname=mydb', 'user', 'pass');
$max = 10;
$min = 0;
$q = $_GET['q'];
$result = $pdo->prepare("SELECT * FROM fruits WHERE name LIKE ? LIMIT ?, ?");
$result->execute(array('%'.$q.'%', $min, $max));
但是,当我用LIMIT 0,LIMIT 10替换LIMIT并从数组中删除$ min和$ max时,它不起作用(不返回任何内容). 我究竟做错了什么?我尝试使用"0"而不是0,但是它也不起作用...
However it doesn't work (returns nothing) while when I replace LIMIT by LIMIT 0, 10 and remove $min and $max from the array it works. What am I doing wrong? I tried using '0' instead of 0 but it doesn't work either...
推荐答案
PDO :: execute将所有参数转义为STRING.
PDO::execute escapes all params as STRING.
$pdo = new PDO('mysql:host=localhost;dbname=mydb', 'user', 'pass');
$max = 10;
$min = 0;
$q = (isset($_GET['q']) && is_string($_GET['q'])) ? $_GET['q'] : '';
$stmt = $pdo->prepare('SELECT * FROM fruits WHERE name LIKE ? LIMIT ?, ?');
$stmt->bindValue(1, "%{$q}%", PDO::PARAM_STR);
$stmt->bindValue(2, $min , PDO::PARAM_INT);
$stmt->bindValue(3, $max , PDO::PARAM_INT);
$stmt->execute();
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