生成R中列表的所有不同排列 [英] Generating all distinct permutations of a list in R

问题描述

我正在尝试创建列表的排列列表，例如，perms(list("a", "b", "c"))返回

I'm trying to create a list of permutations of a list, such that, for example, perms(list("a", "b", "c")) returns

list(list("a", "b", "c"), list("a", "c", "b"), list("b", "a", "c"),
     list("b", "c", "a"), list("c", "a", "b"), list("c", "b", "a"))

我不确定该如何进行，将不胜感激.

I'm not sure how to proceed, any help would be greatly appreciated.

推荐答案

combinat::permn将完成该工作:

> library(combinat)
> permn(letters[1:3])
[[1]]
[1] "a" "b" "c"

[[2]]
[1] "a" "c" "b"

[[3]]
[1] "c" "a" "b"

[[4]]
[1] "c" "b" "a"

[[5]]
[1] "b" "c" "a"

[[6]]
[1] "b" "a" "c"

请注意，如果元素很大，则计算量很大.

Note that calculation is huge if the element is large.

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