在Elixir的Phoenix中全包/通配符路线? [英] Catch-all/wildcard route in Elixir's Phoenix?

问题描述

Phoenix路由器中是否存在可以用作通配符的路由?

In the Phoenix router is there a route that could act as a wildcard?

推荐答案

啊，著名的神奇宝贝路线:

Ah, the famous pokemon route:

get "/*path"

您会在conn.params["path"]内部或conn.path_info中找到路径.

You will find the paths inside conn.params["path"] or as conn.path_info.

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