如何使用"*" IOS中的char? [英] How to call (dialing) with " * " char in IOS?
本文介绍了如何使用"*" IOS中的char?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我希望用*字符致电.例如:* 711313.
I hope to call with * character. ex> *711313.
当前,我正在使用以下代码:
Currently, I'm using this code:
NSString *str = [NSString stringWithFormat:@"tel:%@", tmp];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]];
我测试了两种情况:
-
tmp = @"719929292"; //还行吧.打电话.
tmp = @"719929292"; //this is ok. make call.
tmp = @"* 7128282"; //app没有反应.不打电话.
tmp = @"*7128282"; //app no reaction. not to call.
如何用*(星号)呼叫?
How can I call with *(star character)?
推荐答案
可能必须对星形进行编码才能在URL中使用.尝试使用%2A
代替*
.
The star may have to be encoded for use in a URL. Try %2A
instead of *
.
由于*
是有效的URL字符,尽管具有特殊含义,但stringByAddingPercentEscapesUsingEncoding:
不会执行此替换.
This replacement is not done by stringByAddingPercentEscapesUsingEncoding:
since *
is a valid URL character, albeit with a special meaning.
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