我想拨打电话号码“#51234"，在Xcode中使用telprompt [英] I want to call phone number "#51234" in Xcode use telprompt

问题描述

我要使用telprompt拨打Xcode中的电话号码#51234".

I want to call phone number "#51234" in Xcode use telprompt.

但是telprompt拒绝了它.

but telprompt is reject it.

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"telprompt://#5%@", nzoneNum]]];

nzomeNum为"1234"

nzomeNum is "1234"

推荐答案

至少从iOS 11开始，一个可以拨打带有井号(#)或星号(*)的号码.

At least as of iOS 11, one can dial numbers with a hashtag (#) or asterisk (*).

首先用编码电话号码，然后添加tel:前缀，最后将得到的字符串转换为URL，以使用这些字符进行呼叫.

Make calls with these characters by first encoding the phone number, then adding the tel: prefix, and finally turning the resulting string into a URL.

Swift 4，iOS 11

// set up the dial sequence
let nzoneNum = "1234"
let prefix = "#5"
let dialSequence = "\(prefix)\(nzoneNum)"

// "percent encode" the dial sequence with the URL Host allowed character set
guard let encodedDialSequence =
    dialSequence.addingPercentEncoding(withAllowedCharacters: .urlHostAllowed) else {
    print("Unable to encode the dial sequence.")
    return
}

// add the `tel:` url scheme to the front of the encoded string
let dialURLString = "tel:\(encodedDialSequence)"

// set up the URL with the scheme/encoded number string
guard let dialURL = URL(string: dialURLString) else {
    print("Couldn't make the dial string into an URL.")
    return
}

// dial the URL
UIApplication.shared.open(dialURL, options: [:]) { success in
    if success { print("SUCCESSFULLY OPENED DIAL URL") }
    else { print("COULDN'T OPEN DIAL URL") }
}

Objective-C，iOS 11

// set up the dial sequence
NSString *nzoneNum = @"1234";
NSString *prefix = @"#5";
NSString *dialSequence = [NSString stringWithFormat:@"%@%@", prefix, nzoneNum];

// set up the URL Host allowed character set, and "percent encode" the dial sequence
NSCharacterSet *urlHostAllowed = [NSCharacterSet URLHostAllowedCharacterSet];
NSString *encodedDialSequence = [dialSequence stringByAddingPercentEncodingWithAllowedCharacters:urlHostAllowed];

// add the `tel` url scheme to the front of the encoded string
NSString *dialURLString = [NSString stringWithFormat:@"tel:%@", encodedDialSequence];

// set up the URL with the scheme/encoded number string
NSURL *dialURL = [NSURL URLWithString:dialURLString];

// set up an empty dictionary for the options parameter
NSDictionary *optionsDict = [[NSDictionary alloc] init];

// dial the URL
[[UIApplication sharedApplication] openURL:dialURL
                                   options:optionsDict
                         completionHandler:^(BOOL success) {
                             if (success) { NSLog(@"SUCCESSFULLY OPENED DIAL URL"); }
                             else { NSLog(@"COULDN'T OPEN DIAL URL"); }
                         }];

这篇关于我想拨打电话号码“#51234"，在Xcode中使用telprompt的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！