删除多个空格 [英] Remove multiple whitespaces

问题描述

我正在从MySQL数据库中获取$row['message']，我需要删除所有空白，例如\n \t等.

I'm getting $row['message'] from a MySQL database and I need to remove all whitespace like \n \t and so on.

$row['message'] = "This is   a Text \n and so on \t     Text text.";

应设置为:

$row['message'] = 'This is a Text and so on Text text.';

我尝试过:

 $ro = preg_replace('/\s\s+/', ' ',$row['message']);
 echo $ro;

，但不会删除\n或\t，仅删除单个空格.谁能告诉我该怎么做?

but it doesn't remove \n or \t, just single spaces. Can anyone tell me how to do that?

推荐答案

您需要:

$ro = preg_replace('/\s+/', ' ',$row['message']);

您使用的是\s\s+，表示空格(空格，制表符或换行符)后跟一个或多个空格.这实际上意味着用单个空格替换两个或多个空格.

You are using \s\s+ which means whitespace(space, tab or newline) followed by one or more whitespace. Which effectively means replace two or more whitespace with a single space.

您想要的是用单个空格替换一个或多个空格，因此您可以使用模式\s\s*或\s+(推荐)

What you want is replace one or more whitespace with single whitespace, so you can use the pattern \s\s* or \s+ (recommended)

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