正则表达式模式，以匹配带有或不带有http://www的url [英] Regular expression pattern to match url with or without http://www

问题描述

我根本不擅长正则表达式.

I'm not very good at regular expressions at all.

到目前为止，我一直在使用许多框架代码，但是我找不到能够与http://www.example.com/etcetc之类的URL匹配但又能够捕获诸如www.example.com/etcetc和example.com/etcetc之类的URL的代码.

I've been using a lot of framework code to date, but I'm unable to find one that is able to match a URL like http://www.example.com/etcetc but also is able to catch something like www.example.com/etcetc and example.com/etcetc.

任何帮助都会很棒.谢谢你们！

Any help would be great. Thanks guys!

推荐答案

要匹配所有类型的URL，应使用以下代码:

For matching all kind of URLs following code should work:

<?php
    $regex = "((https?|ftp)://)?"; // SCHEME
    $regex .= "([a-z0-9+!*(),;?&=$_.-]+(:[a-z0-9+!*(),;?&=$_.-]+)?@)?"; // User and Pass
    $regex .= "([a-z0-9\-\.]*)\.(([a-z]{2,4})|([0-9]{1,3}\.([0-9]{1,3})\.([0-9]{1,3})))"; // Host or IP
    $regex .= "(:[0-9]{2,5})?"; // Port
    $regex .= "(/([a-z0-9+$_%-]\.?)+)*/?"; // Path
    $regex .= "(\?[a-z+&\$_.-][a-z0-9;:@&%=+/$_.-]*)?"; // GET Query
    $regex .= "(#[a-z_.-][a-z0-9+$%_.-]*)?"; // Anchor
?>

然后，检查正则表达式的正确方法如下:

Then, the correct way to check against the regex is as follows:

<?php
   if(preg_match("~^$regex$~i", 'www.example.com/etcetc', $m))
      var_dump($m);

   if(preg_match("~^$regex$~i", 'http://www.example.com/etcetc', $m))
      var_dump($m);
?>

Courtesy: splattermania 在PHP手册上发表的评论:

Courtesy: Comments made by splattermania on PHP manual: http://php.net/manual/en/function.preg-match.php

regex101中的RegEx演示

RegEx Demo in regex101

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