网址不存在时的file_get_contents [英] file_get_contents when url doesn't exist

问题描述

我正在使用file_get_contents()访问URL.

I'm using file_get_contents() to access a URL.

file_get_contents('http://somenotrealurl.com/notrealpage');

如果URL不是真实的，它将返回此错误消息.我如何才能使其优雅地出错，以使我知道该页面不存在，并在不显示此错误消息的情况下采取相应措施?

If the URL is not real, it return this error message. How can I get it to error gracefully so that I know that the page doesn't exist and act accordingly without displaying this error message?

file_get_contents('http://somenotrealurl.com/notrealpage') 
[function.file-get-contents]: 
failed to open stream: HTTP request failed! HTTP/1.0 404 Not Found 
in myphppage.php on line 3

例如在zend中，您可以说:if ($request->isSuccessful())

for example in zend you can say: if ($request->isSuccessful())

$client = New Zend_Http_Client();
$client->setUri('http://someurl.com/somepage');

$request = $client->request();

if ($request->isSuccessful()) {
 //do stuff with the result
}

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