正则表达式PHP-从img标签中隔离src属性 [英] Regex & PHP - isolate src attribute from img tag

问题描述

使用PHP，如何隔离$ foo的src属性的内容?我要寻找的最终结果只会是" http://example.com/img/image. jpg "

With PHP, how can I isolate the contents of the src attribute from $foo? The end result I'm looking for would give me just "http://example.com/img/image.jpg"

$foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';

推荐答案

如果您不希望使用正则表达式(或任何非标准的PHP组件)，请使用内置的

If you don't wish to use regex (or any non-standard PHP components), a reasonable solution using the built-in DOMDocument class would be as follows:

<?php
    $doc = new DOMDocument();
    $doc->loadHTML('<img src="http://example.com/img/image.jpg" ... />');
    $imageTags = $doc->getElementsByTagName('img');

    foreach($imageTags as $tag) {
        echo $tag->getAttribute('src');
    }
?>

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