使用preg_match检测网址?字符串中不含http:// [英] Detecting a url using preg_match? without http:// in the string

问题描述

我想知道如何根据preg_match检查分成数组的字符串，看看它是否以www开头.我已经有一个可以检查 http://www 了.

I was wondering how I could check a string broken into an array against a preg_match to see if it started with www. I already have one that check for http://www.

function isValidURL($url)
{
return preg_match('|^http(s)?://[a-z0-9-]+(.[a-z0-9-]+)*(:[0-9]+)?(/.*)?$|i', $url);
}

$stringToArray = explode(" ",$_POST['text']);

  foreach($stringToArray as $key=>$val){
  $urlvalid = isValidURL($val);
  if($urlvalid){
  $_SESSION["messages"][] = "NO URLS ALLOWED!";
  header("Location: http://www.domain.com/post/id/".$_POST['postID']);
     exit();
     }
     }

谢谢！ 斯蒂芬

推荐答案

您想要类似的东西

%^((https?://)|(www\.))([a-z0-9-].?)+(:[0-9]+)?(/.*)?$%i

这是使用|在开头匹配http://或www.我将分隔符更改为%，以避免与|

this is using the | to match either http:// or www at the beginning. I changed the delimiter to % to avoid clashing with the |

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