如何将更改后的SimpleXML对象保存回文件? [英] How to save changed SimpleXML object back to file?

问题描述

因此，我有这段代码可以搜索我的XML文件中的特定节点，取消设置现有节点并插入带有正确数据的全新子节点.有没有一种方法可以使用simpleXML将这些新数据保存在实际的XML文件中?如果没有，还有其他有效的方法吗?

So, I have this code that searches for a particular node in my XML file, unsets an existing node and inserts a brand new child node with the correct data. Is there a way of getting this new data to save within the actual XML file with simpleXML? If not, is there another efficient method for doing this?

public function hint_insert() {

    foreach($this->hints as $key => $value) {

        $filename = $this->get_qid_filename($key);

        echo "$key - $filename - $value[0]<br>";

        //insert hint within right node using simplexml
        $xml = simplexml_load_file($filename);

        foreach ($xml->PrintQuestion as $PrintQuestion) {

            unset($xml->PrintQuestion->content->multichoice->feedback->hint->Passage);

            $xml->PrintQuestion->content->multichoice->feedback->hint->addChild('Passage', $value[0]);

            echo("<pre>" . print_r($PrintQuestion) . "</pre>");
            return;

        }

    }

}

推荐答案

不确定我是否理解此问题. asXML() 方法接受可选的文件名作为参数，以保存当前结构作为XML到文件.因此，一旦使用提示更新了XML，只需将其保存回文件中即可.

Not sure I understand the issue. The asXML() method accepts an optional filename as param that will save the current structure as XML to a file. So once you have updated your XML with the hints, just save it back to file.

// Load XML with SimpleXml from string
$root = simplexml_load_string('<root><a>foo</a></root>');
// Modify a node
$root->a = 'bar';
// Saving the whole modified XML to a new filename
$root->asXml('updated.xml');
// Save only the modified node
$root->a->asXml('only-a.xml');

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