字符串作为PHP中的数组 [英] Strings as arrays in php

问题描述

我知道php中的字符串是.....字符串，但是例如我可以做到

I know that strings in php are ..... strings but for example I can do

$str = 'String';
echo $str[0];
echo $str[1];

//result
S
t

echo count($str)
//result
1

为什么我可以像穿过数组那样走过它们，却不能用count来计数? (我知道我可以使用strlen())

Why I can walk trough them like in an array but can't count them with count? (I know that I can use strlen() )

推荐答案

因为它是这样工作的.您可以使用方括号符号访问特定的字节偏移量.但这并不意味着字符串是一个数组，您可以使用期望在其上放置数组的函数. $string[int]是substr($string, int, 1)的语法糖，仅此而已.

Because that's how it works. You can access specific byte offsets using bracket notation. But that doesn't mean the string is an array and that you can use functions which expect arrays on it. $string[int] is syntactic sugar for substr($string, int, 1), nothing more, nothing less.

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