比较对象属性并在PHP中显示差异 [英] compare object properties and show diff in PHP

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本文介绍了比较对象属性并在PHP中显示差异的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在寻找一种方法来显示给定对象的不同属性/值...

I'm searching for a way to show me the different properties/values from given objects...

$obj1 = new StdClass; $obj1->prop = 1;
$obj2 = new StdClass; $obj2->prop = 2;

var_dump(array_diff((array)$obj1, (array)$obj2));
//output array(1) { ["prop"]=> int(1) }

只要属性不是对象或数组,此方法就可以很好地工作.

This works very well as long the property is not a object or array.

$obj1 = new StdClass; $obj1->prop = array(1,2);
$obj2 = new StdClass; $obj2->prop = array(1,3); 

var_dump(array_diff((array)$obj1, (array)$obj2))
// Output array(0) { }
// Expected output - array { ["prop"]=> array { [1]=> int(2) } }

即使该属性是另一个对象,有没有办法摆脱这种情况?!

Is there a way to get rid of this, even when the property is another object ?!

推荐答案

类似于下面的过程,它迭代并进行递归比较是数组中的项本身就是数组可以工作:

Something like the following, which iterates through and does a recursive diff is the item in the array is itself an array could work:

与array_diff的工作类似,但是会检查它是否首先是一个数组(is_array),如果是,则将该键的diff设置为该数组的diff.递归地重复.

Des similar work to array_diff, but it does a check to see if it is an array first (is_array) and if so, sets the diff for that key to be the diff for that array. Repeats recursively.

function recursive_array_diff($a1, $a2) { 
    $r = array(); 
    foreach ($a1 as $k => $v) {
        if (array_key_exists($k, $a2)) { 
            if (is_array($v)) { 
                $rad = recursive_array_diff($v, $a2[$k]); 
                if (count($rad)) { $r[$k] = $rad; } 
            } else { 
                if ($v != $a2[$k]) { 
                    $r[$k] = $v; 
                }
            }
        } else { 
            $r[$k] = $v; 
        } 
    } 
    return $r; 
}

它的工作原理如下:

$obj1 = new StdClass; $obj1->prop = array(1,2);
$obj2 = new StdClass; $obj2->prop = array(1,3);
print_r(recursive_array_diff((array)$obj1, (array)$obj2));

/* Output:
    Array
    (
        [prop] => Array
            (
                [1] => 2
            )
    )
*/

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