如何使用RegEx删除html元素及其内容 [英] How can I remove an html element and it's contents using RegEx

问题描述

我有一个要从看起来像这样的输出中删除的div ID

I have a div id like to remove from an output which looks like

<div id="ithis" class="cthis">Content here which includes other elements etc..) </div>

如何使用PHP和regex删除此div及其中的所有内容?

How can I remove this div and everything within it using PHP and regex?

谢谢.

推荐答案

简单的答案是您没有.您可以使用PHP的许多HTML解析器之一.正则表达式是一种处理HTML的易碎且容易出错的方式.

The simple answer is that you don't. You use one of PHP's many HTML parsers instead. Regexes are a flaky and error-prone way of manipulating HTML.

话虽如此，您可以执行以下操作:

That being said you can do this:

$html = preg_replace('!<div\s+id="ithis"\s+class="cthis">.*?</div>!is', '', $html);

但是很多可能会出错.例如，如果其中包含div:

But many things can wrong with this. For example, if that contains a div:

<div id="ithis" class="cthis">Content here which <div>includes</div> other elements etc..) </div>

您最终会得到:

 other elements etc..) </div>

，因为正则表达式将在第一个</div>处停止.而且，没有什么真正可以做的事情(用正则表达式)一致地解决这个问题.

as the regex will stop at the first </div>. And no there's nothing you can really do to solve this problem (with regular expressions) consistently.

使用解析器完成后，它看起来更像这样:

Done with a parser it looks more like this:

$doc = new DOMDocument();
$doc->loadHTML($html);
$element = $doc->getElementById('ithis');
$element->parentNode->removeChild($element);
$html = $doc->saveHTML();

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