在PHP中减去两个日期 [英] Subtracting two dates in php

问题描述

我在php中有两个约会

I have got two dates in php

$date1 = 'May 3, 2012 10:38:22 GMT'

$date2 = '06 Apr 2012 07:22:21 GMT'

然后我将它们都减去

$date2 - $date1

，然后获取

Result:6

为什么结果是6而不是27? ...?如何减去这两个日期，并使其减去月份& ;;天和时间?

Why is the result 6 and not 27? ... ? How can I subtract the two dates, and make it return me a result based on month differences while subtracting the years & days & time ?

推荐答案

第1部分:为什么结果为6?

Part 1: Why is the result 6?

当您初次减去日期时，它们只是字符串. PHP尝试将它们转换为整数.它通过转换直到第一个非数字来完成此操作.因此，date2变为6，date1变为0.

The dates are simply strings when you first subtract them. PHP attempts to convert them to integers. It does this by converting until the first non-number. So, date2 become 6 and date1 becomes 0.

第2部分:如何使用它?

Part 2: How do you get it to work?

$datetime1 = strtotime('May 3, 2012 10:38:22 GMT');
$datetime2 = strtotime('06 Apr 2012 07:22:21 GMT');

$secs = $datetime2 - $datetime1;// == <seconds between the two times>
$days = $secs / 86400;

进行适当的转换.

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