使用PHP创建XML网站地图 [英] Creating an XML sitemap with PHP

问题描述

我正在尝试创建一个将自动更新的站点地图.我已经用RSS提要完成了类似的操作，但是此站点地图无法正常工作.您可以在 http://designdeluge.com/sitemap.xml 上实时查看它，我认为主要问题是它无法识别PHP代码.这是完整的来源:

I'm trying to create a sitemap that will automatically update. I've done something similiar with my RSS feed, but this sitemap refuses to work. You can view it live at http://designdeluge.com/sitemap.xml I think the main problem is that its not recognizing the PHP code. Here's the full source:

 <?php 


include 'includes/connection.php';

header("Content-type: text/xml");

echo '<?xml version="1.0" encoding="UTF-8" ?>';

?>

<urlset xmlns="http://www.google.com/schemas/sitemap/0.84" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.google.com/schemas/sitemap/0.84 http://www.google.com/schemas/sitemap/0.84/sitemap.xsd">

    <url>
        <loc>http://designdeluge.com/</loc>
        <lastmod>2010-04-20</lastmod>
        <changefreq>weekly</changefreq>
        <priority>1.00</priority>
    </url>

    <url>
        <loc>http://designdeluge.com/about.php</loc>
        <lastmod>2010-04-20</lastmod>
        <changefreq>never</changefreq>
        <priority>0.5</priority>
    </url>

    <?php

    $entries = mysql_query("SELECT * FROM Entries");

    while($row = mysql_fetch_assoc($entries)) {
    $title = stripslashes($row['title']);
    $date = date("Y-m-d", strtotime($row['timestamp']));

    echo "

    <url>
        <loc>http://designdeluge.com/".$title."</loc>
        <lastmod>".$date."</lastmod>
        <changefreq>never</changefreq>
        <priority>0.8</priority>
    </url>";

 } ?>

</urlset>

问题是动态URL(例如从数据库中提取的URL)没有生成，站点地图也无法验证.谢谢！

The problem is that the dynamic URL's (e.g. the ones pulled from the DB) aren't being generated and the sitemap won't validate. Thanks!

编辑:现在，我只是在尝试使代码本身正常工作.我将其设置为本地测试服务器上的PHP文件.上面的代码正在使用中.现在，在屏幕上或源代码中什么也没有显示.我以为我犯了语法错误，但找不到任何东西.任何帮助都将不胜感激！

Right now, I'm just trying to get the code itself working. I have it set up as a PHP file on my local testing server. The code above is being used. Right now, nothing displays nothing on screen or in the source. I'm thinking I made a syntax error, but I can't find anything. Any and all help is appreciated!

好的，我把它整理出来了.显然，我不得不用PHP回显xml声明.最终代码已发布在上方.感谢您的帮助！

EDIT 2: Ok, I got it sorted out guys. Apparently, I had to echo the xml declaration with PHP. The final code is posted above. Thanks for your help!

推荐答案

如果您查看生成的sitemap.xml (例如，使用浏览器中的视图源)，则您会看到的:

If you take a look at the sitemap.xml that's generated (using view source, in your browser, for example), you'll see this :

<?php header('Content-type: text/xml'); ?>
<?xml version="1.0" encoding="UTF-8" ?>
<urlset xmlns="http://www.google.com/schemas/sitemap/0.84" xmlns:xsi="http:/
...

该输出中显示的<?php表明 PHP代码未得到解释.

这可能是因为您的网络服务器无法将.xml识别为应该包含PHP代码的文件的扩展名.

This is probably because your webserver doesn't recognize .xml as an extension of files that should contain PHP code.

至少两个可能的解决方案:

At least two possible solutions :

• 重新配置服务器，以便XML文件通过PHP解释器(可能不是一个好主意:可能会导致现有文件出现问题！)
• 将站点地图的扩展名更改为sitemap.php，以便由服务器解释.

• Re-configure your server, so XML files go through the PHP interpreter (might not be such a good idea : that can cause problems with existing files ! )
• Change the extension of your sitemap, to sitemap.php for example, so it's interpreted by your server.

我会添加另一个解决方案:

I would add another solution :

• 具有一个sitemap.php文件，其中包含代码
• 然后使用RewriteRule ，因此sitemap.xml URL实际上指向sitemap.php文件

• Have a sitemap.php file, that contains the code
• And use a RewriteRule so the sitemap.xml URL actually points to the sitemap.php file

有了它，您将拥有sitemap.xml URL，这是不错的(必需?)，但由于代码将在sitemap.php中，因此将得到解释.

With that, you'll have the sitemap.xml URL, which is nice (required ? ), but as the code will be in sitemap.php, it'll get interpreted.

请参见 Apache的mod_rewrite

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