使用imagick使图像圆形化 [英] circularize an image with imagick

问题描述

尝试拍摄矩形照片，将其裁剪为正方形区域，然后将其蒙版为具有透明背景的圆形.

Trying to take a rectangular photo, crop it into a square region, and then mask it into a circular with a transparent background.

//$dims is an array with the width, height, x, y of the region in the rectangular image (whose path on disk is $tempfile)

$circle = new \Imagick();
$circle->newImage($dims['w'], $dims['h'], 'none');
$circle->setimageformat('png');
$circle->setimagematte(true);
$draw = new \ImagickDraw();
$draw->setfillcolor('#ffffff');
$draw->circle($dims['w']/2, $dims['h']/2, $dims['w']/2, $dims['w']);
$circle->drawimage($draw);

$imagick = new \Imagick();
$imagick->readImage($tempfile);
$imagick->setImageFormat( "png" );
$imagick->setimagematte(true);
$imagick->cropimage($dims['w'], $dims['h'], $dims['x'], $dims['y']);
$imagick->compositeimage($circle, \Imagick::COMPOSITE_DSTIN, 0, 0);
$imagick->writeImage($tempfile);
$imagick->destroy();

结果是矩形图像，未裁剪且未圆形化.我在做什么错了?

The result is the rectangular image, uncropped and without being circularized. What am I doing wrong?

示例图片:

$ dims = {"x":253，"y":0，"x2":438.5，"y2":185.5，"w":185.5，"h":185.5}的示例输入

Example input for $dims = {"x":253,"y":0,"x2":438.5,"y2":185.5,"w":185.5,"h":185.5}

粗略预期输出:

我得到的图像看起来大致类似于输入图像.

Image i'm getting looks roughly like the input image.

推荐答案

这对我有用:

<?php
//$dims is an array with the width, height, x, y of the region in the rectangular image (whose path on disk is $tempfile)
$tempfile = 'VDSlU.jpg';
$outfile = 'blah.png';

$circle = new Imagick();
$circle->newImage(185.5, 185.5, 'none');
$circle->setimageformat('png');
$circle->setimagematte(true);
$draw = new ImagickDraw();
$draw->setfillcolor('#ffffff');
$draw->circle(185.5/2, 185.5/2, 185.5/2, 185.5);
$circle->drawimage($draw);

$imagick = new Imagick();
$imagick->readImage($tempfile);
$imagick->setImageFormat( "png" );
$imagick->setimagematte(true);
$imagick->cropimage(185.5, 185.5, 253, 0);
$imagick->compositeimage($circle, Imagick::COMPOSITE_DSTIN, 0, 0);
$imagick->writeImage($outfile);
$imagick->destroy();
?>

<img src="blah.png">

我总是尝试使代码保持简单，直到我能正常工作，然后添加所有变量等.这可能是问题，或者您的Imagick版本可能有问题.

I always try to keep the code simple until I get it working and then add all the variables etc. That could be the problem or there could be a problem with your version of Imagick.

它是命名空间

It's namespaced

还是不知道是什么意思！ -我对php有所了解，因为这些天我不太使用它.

Still do not know what it means! - I am getting a bit behind with php as I do not use it very much these days.

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