PHP-如何捕获“试图获取非对象的属性"错误 [英] PHP - How to catch a 'Trying to get property of non-object' error

问题描述

我正在尝试通过try/catch语句捕获试图获取非对象的属性"错误，但失败了，但仍然出现PHP错误.我正在使用:

I am trying to catch 'Trying to get property of non-object' error with a try/catch statement but it is failing, I still get a PHP error. I am using as:

try{
  $id = Model()->find('id=1')->id;
}catch(Exception $e){
  echo 'failed';
}

我的find函数返回一个对象(活动记录)，我可以通过对象prop来访问id列.

My find function returns an object (Active Record) and I can access the id column as shown via object prop.

但是，如果未找到AR，它将为空对象.我认为try语句会抓住这一点.我自己的解决方法是使用isset().但是我对为什么try语句不接受并捕获此错误感到困惑.

However, it will be null object if AR is not found. I thought the try statement would catch this. A work around for myself would be to use an isset(). But I am confused as to why the try statement does not accept and catch this error.

推荐答案

try..catch适用于抛出的异常. 错误也不例外.您可以静音错误，但请不要这样做.相反，请正确检查您得到的内容:

try..catch works on thrown exceptions. Errors are not exceptions. You can silence errors, but please don't do that. Instead, properly check what you're getting:

$result = Model()->find('id=1');
if ($result) {
    $id = $result->id;
} else {
    // handle this situation
}

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