一个explode()函数会忽略引号内的字符? [英] An explode() function that ignores characters inside quotes?

问题描述

有人知道快速，简单的explode()这样的函数可以忽略用一对任意字符(例如，引号)引起的分隔符吗?

Does somebody know a quick and easy explode() like function that can ignore splitter characters that are enclosed in a pair of arbitrary characters (e.g. quotes)?

示例:

my_explode(
  "/", 
  "This is/a string/that should be/exploded.//But 'not/here',/and 'not/here'"
);

应导致包含以下成员的数组:

should result in an array with the following members:

This is
a string 
that should be 
exploded.

But 'not/here', 
and 'not/here'

将字符用单引号引起来的事实将使它们免于分隔符的使用.

the fact that the characters are wrapped in single quotes would spare them from being splitters.

奖励积分可解决两个包装字符

Bonus points for a solution that can deal with two wrapper characters

(not/here)

首选本机PHP解决方案，但我认为不存在这种情况！

A native PHP solution would be preferred, but I don't think such a thing exists!

推荐答案

($str, '/')

在链接的页面上有一个< 5.3的配方.

There's a recipe for <5.3 on the linked page.

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