如何获取两个dateTime obj之间的毫秒数? [英] How to get millisecond between two dateTime obj?

问题描述

如何获取两个DateTime对象之间的毫秒数?

How to get millisecond between two DateTime objects?

$date = new DateTime();
$date2 = new DateTime("1990-08-07 08:44");

我尝试遵循以下评论，但出现错误.

I tried to follow the comment below, but I got an error.

$stime = new DateTime($startTime->format("d-m-Y H:i:s"));
$etime = new DateTime($endTime->format("d-m-Y H:i:s")); 
$millisec = $etime->getTimestamp() - $stime->getTimestamp();` 

我得到了错误

调用未定义的方法DateTime :: getTimestamp()

Call to undefined method DateTime::getTimestamp()

推荐答案

从严格意义上讲，你做不到.

In the strict sense, you can't.

这是因为DateTime类的最小时间单位是一秒钟.

It's because the smallest unit of time for the DateTime class is a second.

如果您需要一个包含毫秒的测量值，请使用 microtime()

If you need a measurement containing milliseconds then use microtime()

另一方面，如果您只是想获取两个 ISO-8601日期时间之间的间隔(以毫秒为单位)那么一个可能的解决方案是

On the other hand if you simply want to get the interval in milliseconds between two ISO-8601 datetimes then one possible solution would be

function millisecsBetween($dateOne, $dateTwo, $abs = true) {
    $func = $abs ? 'abs' : 'intval';
    return $func(strtotime($dateOne) - strtotime($dateTwo)) * 1000;
}

请注意，默认情况下，以上函数将返回绝对差.如果您想知道第一个日期是否早些，则将第三个参数设置为false.

Beware that by default the above function returns absolute difference. If you want to know whether the first date is earlier or not then set the third argument to false.

// Outputs 60000
echo millisecsBetween("2010-10-26 20:30", "2010-10-26 20:31");

// Outputs -60000 indicating that the first argument is an earlier date
echo millisecsBetween("2010-10-26 20:30", "2010-10-26 20:31", false);

在时间数据类型为32位的系统(例如Windows7或更早版本)上，millisecsBetween仅适用于1970-01-01 00:00:00和2038-01-19 03:14:07之间的日期(请参阅

On systems where the size of time datatype is 32 bits, such as Windows7 or earlier, millisecsBetween is only good for dates between 1970-01-01 00:00:00 and 2038-01-19 03:14:07 (see Year 2038 problem).

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