数组中的PHP字符串仅返回第一个字符 [英] PHP String in Array Only Returns First Character

问题描述

在接下来的一周里，我陷入了一个非常缓慢的1条EDGE互联网连接，所以请原谅我，如果我没有花足够的时间研究这一点，但是我只是设置了一个本地服务器进行测试我通常会在Internet上测试的代码，但在本地LAMP安装上似乎无法正常工作.

For the next week, I'm stuck with a sadly very slow 1-bar EDGE internet connection, so forgive me if I didn't spend quite enough time researching this one, but I just set up a local server for testing code that I would normally test over the internet, and it doesn't seem to be working the same way on my local LAMP install.

问题是，当我这样做时:

The issue is, when I do this:

echo strtolower($_REQUEST['page']);

结果是这样的:

files

但是，当我这样做时:

$page['name'] = strtolower($_REQUEST['page']);
echo $page['name'];

结果是这样的:

f

否，这不是错字，它始终仅返回字符串的第一个字母.进行var_dump($page)将导致string(5) "files"，但是进行var_dump($page['name'])将导致string(1) "f".我正在使用PHP 5.2.1.

No, that's not a typo, it consistently returns only the first letter of the string. Doing a var_dump($page) will result in string(5) "files", but doing a var_dump($page['name']) will result in string(1) "f". I'm using PHP 5.2.1.

这是怎么回事?

推荐答案

您几乎回答了自己的问题. $page是文件"(如您的第一个var_dump所示).这可能是由于已弃用的register_globals或其手动近似导致的.鉴于此，

You pretty much answered your own question. $page is "files" (as shown by your first var_dump). This could be caused by the deprecated register_globals, or a manual approximation thereof. Given that,

$page['files']

是"f".这是因为非数字字符串被隐式转换为0(！).您可以使用以下方法轻松重现此内容:

is "f". This is because non-numeric strings are implicitly converted to 0 (!). You can reproduce this easily with:

$page = 'files';
echo $page['files'];

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