替换所有的"foo"之间 () [英] replace all "foo" between ()

问题描述

我的正则表达式代码有问题，问题是:我想替换所有"foo"值，但只替换()"内部.示例:

I've problem with my regex code, the problem is: I want to replace all "foo" values but only inside "()". Example:

try foo foo-foo (try foo inside , foo foo foofoo)

我想用"boo"替换括号之间的所有"foo"字符串.

I want to replace all "foo" strings between the parentheses by "boo".

推荐答案

假定括号是有效的"，则可以替换所有foo，后跟)，而在中间没有(.

Assuming parentheses are "valid", you can replace all foos that are followed by ), without a ( in between:

$str = preg_replace('/foo(?=[^()]*\))/', 'bar', $str);

工作示例: http://ideone.com/xezU7

另一个假设没有嵌套对的选项是匹配"(...)"令牌并使用回调，但是可能使用了过多的力:

Another option, also assuming no nested pairs, is to match "(...)" tokens and use a callback, but it may be use of excessive force:

回调方法:

function replace_foo($matches) {
   return str_replace('foo', 'bar', $matches[0]);
}

使用:

$str = preg_replace_callback("/\([^()]*\)/","replace_foo", $str);

工作示例: http://ideone.com/ZzBem

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