获取包含PHP脚本的文件的名称 [英] Get name of file that is including a PHP script

问题描述

以下是我要执行的操作的示例:

Here is an example of what I am trying to do:

<ul><?php include("list.php") ?></ul>

list.php

<?php
    if (PAGE_NAME is index.php) {
        //Do something
    }
    else {
        //Do something
    }
?>

如何获取包含list.php脚本(PAGE_NAME)的文件的名称?我已经尝试过basename(__FILE__)，但这给了我list.php.

How can I get the name of the file that is including the list.php script (PAGE_NAME)? I have tried basename(__FILE__), but that gives me list.php.

推荐答案

$_SERVER["PHP_SELF"];返回您想要的内容

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