PHP日期:获得不同年份的日期 [英] PHP Date : get date different in years

问题描述

这是我的代码:

date_default_timezone_set('Asia/Kuala_Lumpur');
$date_join = $row['date_joined']; =produce 2012-09-03
$today = date("Y-m-d");   = produce 2014-08-29

$objPHPExcel->setActiveSheetIndex(0)->setCellValue('H'.$a, **$xxx**);

如何获取像年这样的日期持续时间($ today-$ date_join):

how can i get date durations ($today - $date_join) in years like :

服务日期:1.5年

推荐答案

您可以使用PHP strtotime() function.尝试这样..

You can use PHP strtotime() function. Try like this..

$join_date = '2012-09-03'; //join date
$today = date("Y-m-d"); //current date

$date_join  = strtotime($join_date); // join date to seconds
$today = strtotime($today); //current date to seconds

$differenceInSeconds = $today - $date_join; // Time difference in seconds
echo number_format($differenceInSeconds / (365 * 24 * 60 * 60), 2) . ' Year(s)';

• 获取两个日期之间以秒为单位的时差
• 将差异相差一年等效秒

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