PHPmailer:从表单发送 [英] PHPmailer: Send from form

问题描述

好的，我有我的表单(第一段代码)，并且我正在尝试使用PHPmailer发送它.但是，它发送的消息中没有来自实际表格的任何信息.我对如何使它正常工作感到迷茫.

Alright, I have my form (first snippet of code), and I am trying to use PHPmailer to send it. However, it sends the message without any of the information from the actual form. I am pretty lost with how to get this to work.

<form action="send_form_email.php" method="post" id="ContactForm">
                    <fieldset>
              <p class="email">magazines/newspapers</p>
                        <ol>
                            <li>
                                <label for=name>Name</label>
                                <input id="name" name="name" type="text" placeholder="name" required autofocus>
                            </li>


                            <li>
                                <label for=email>Email</label>
                                <input id="email" name="email" type=email placeholder="[e-mail]" required>
                            </li>

                            <li>
                                <label for=telephone>Phone</label>
                                <input id=telephone name=telephone type=tel placeholder="Eg. 888-555-5555" required>
                            </li>

                            <li>
                            <label for="comments">note</label> 
                <textarea name=comments type=text placeholder="enter your comments" required></textarea>
                            </li>

                            <li>
                            <label for="file">File</label>
                            <input id="file" type="file" name="file" />
                            </li>

                        </ol>
                    </fieldset>

              <fieldset>
                        <button type=submit>submit</button>
                    </fieldset>

                </form>

邮件脚本:

require("mail/class.phpmailer.php");

$mail = new PHPMailer();
$mail->Host = "localhost";               
$mail->From = "[e-mail]";
$mail->FromName  =  "Your Name";
$mail->AddAddress("[e-mail]");


$mail->Subject = "Feedback form results";
$mail->Body = $comments;
$mail->WordWrap = 50;

if(!$mail->Send())
{
   echo 'Message was not sent.';
   echo 'Mailer error: ' . $mail->ErrorInfo;
}
else
{
   echo 'Thank you for your feedback.';
}
  $email = $_REQUEST['email'] ;
  $comments = $_POST['telephone'] ;
    $phone = $_REQUEST['comments'] ;
  $message = $_REQUEST['message'] ;

推荐答案

好，所以第一步(可选)是将发布的变量收集到局部变量中-之前，您进入了$mail=new PHPMailer()...位.对于您提供的有限代码片段来说，这不是必需的，但是您可以在其他地方使用它们.

Ok so step one (optional) is to collect the posted variables into local variables - BEFORE you get into the $mail=new PHPMailer()... bit. This isn't necessary for the limited code fragment you provide, but you might use them somewhere else.

$name = $_POST['name'] ;
$email = $_REQUEST['email'] ;
$telephone = $_REQUEST['telephone'] ;
$comments = $_POST['comments'] ;

现在，将$mail->Body = $comments;行更改为:

$mail->Body="
Name: $name
Email: $email
Telephone: $telephone
Comments: $comments";

ngroot 指出；添加附件:

$mail->AddAttachment($_FILES['file']['tmp_name']);

...，您可以多次调用多个附件.由于表单上载的工作方式(文件存储在临时空间中)，您需要使用此tmp_name子变量.您还需要添加多部分表单编码以允许文件上传，因此表单行应显示为:

... which you can call multiple times for multiple attachments. Because of the way form-uploads work (files get stored in a temporary space) you need to use this tmp_name sub variable. You'll also need to add multipart form encoding to allow file uploads, so the form line should read:

<form enctype="multipart/form-data" action="send_form_email.php" method="post" id="ContactForm"  >

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