将PHPUnit测试类标记为被忽略 [英] Mark a PHPUnit test class as to be ignored
本文介绍了将PHPUnit测试类标记为被忽略的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我已经编写了一个抽象的测试用例类,该类将通过具体的测试用例类进行扩展.
I have written an abstract test case class that is to be extended by concrete test case classes.
它是从 PHPUnit_TestCase 扩展的.
是否存在一种方法或注释,指示Phpunit不执行此抽象测试(但不会将其标记为已跳过或未完成)?
Is there a method or annotation that signals Phpunit to not execute this abstract test (but does not mark it as skipped or incomplete)?
现在,Phpunit也运行抽象测试类,然后报告一个无法实例化它的错误-这是通过语言得出的:无法实例化抽象类.
Right now Phpunit runs the abstract test class as well and then reports an error that it can not instantiate it - which is by language: An abstract class can not be instantiated.
推荐答案
如果命名为FooTest
,则将其重命名为FooTestCase
.
If it is named FooTest
rename it to FooTestCase
.
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