如何在Symfony 2.3的功能测试中的会话中登录用户? [英] How to log in User in Session within a Functional Test in Symfony 2.3?
问题描述
我已经阅读了很多关于stackoverflow的帖子.但是大多数方法在Symfony 2.3中没有用. 因此,我尝试在测试中手动登录用户以在后端执行一些操作. 这是我的security.yml
I have read many posts on stackoverflow about this. But most of the methods not useful in Symfony 2.3. So I have try to log in user manually in test to make some actions in back-end. Here is my security.yml
security:
...
role_hierarchy:
ROLE_SILVER: [ROLE_BRONZE]
ROLE_GOLD: [ROLE_BRONZE, ROLE_SILVER]
ROLE_PLATINUM: [ROLE_BRONZE, ROLE_SILVER, ROLE_GOLD]
ROLE_ADMIN: [ROLE_BRONZE, ROLE_SILVER, ROLE_GOLD, ROLE_PLATINUM, ROLE_ALLOWED_TO_SWITCH]
providers:
database:
entity: { class: Fox\PersonBundle\Entity\Person, property: username }
firewalls:
dev:
pattern: ^/(_(profiler|wdt)|css|images|js)/
security: false
login:
pattern: ^/person/login$
security: false
main:
pattern: ^/
provider: database
form_login:
check_path: /person/login-check
login_path: /person/login
default_target_path: /person/view
always_use_default_target_path: true
logout:
path: /person/logout
target: /
anonymous: true
access_control:
- { path: ^/, roles: IS_AUTHENTICATED_ANONYMOUSLY }
- { path: ^/person/registration, roles: IS_AUTHENTICATED_ANONYMOUSLY }
- { path: ^/person, roles: ROLE_BRONZE }
这是我的考试:
class ProfileControllerTest extends WebTestCase
{
public function setUp()
{
$kernel = self::getKernelClass();
self::$kernel = new $kernel('dev', true);
self::$kernel->boot();
}
public function testView()
{
$client = static::createClient();
$person = self::$kernel->getContainer()->get('doctrine')->getRepository('FoxPersonBundle:Person')->findOneByUsername('master');
$token = new UsernamePasswordToken($person, $person->getPassword(), 'main', $person->getRoles());
self::$kernel->getContainer()->get('security.context')->setToken($token);
self::$kernel->getContainer()->get('event_dispatcher')->dispatch(
AuthenticationEvents::AUTHENTICATION_SUCCESS,
new AuthenticationEvent($token));
$crawler = $client->request('GET', '/person/view');
}
当我运行此测试时,$person = $this->get(security.context)->getToken()->getUser();
方法在测试Controller中不起作用.说如果在控制器调用$person->getId();
中,我将出现错误Call to a member function getId() on a non-object in...
.
And when I run this test, $person = $this->get(security.context)->getToken()->getUser();
method is not working in testing Controller. Say if in controller call $person->getId();
I will have an error Call to a member function getId() on a non-object in...
.
那么您能告诉我在Symfony 2.3的功能测试中登录用户的正确方法吗?
So can you tell the properly way to log in user in functional test in Symfony 2.3?
谢谢!
EDIT_1 :
如果我更改Symfony/Component/Security/Http/Firewall/ContextListener.php
并注释一个字符串:
EDIT_1:
If I change Symfony/Component/Security/Http/Firewall/ContextListener.php
and comment one string:
if (null === $session || null === $token = $session->get('_security_'.$this->contextKey)) {
// $this->context->setToken(null);
return;
}
所有测试均正常进行.
EDIT_2 : 这是我尝试使用的参考: 第一 秒 第三 第四 第五 第六 第七 第八 第九个
EDIT_2: This is reference that i have trying to use: first second third fourth fifth sixth seventh eighth nineth
推荐答案
最后,我解决了!这是工作代码的示例:
Finaly i solve it! This is example of working code:
use Symfony\Bundle\FrameworkBundle\Test\WebTestCase;
use Symfony\Component\Security\Core\Authentication\Token\UsernamePasswordToken;
use Symfony\Component\BrowserKit\Cookie;
class ProfileControllerTest extends WebTestCase
{
protected function createAuthorizedClient()
{
$client = static::createClient();
$container = static::$kernel->getContainer();
$session = $container->get('session');
$person = self::$kernel->getContainer()->get('doctrine')->getRepository('FoxPersonBundle:Person')->findOneByUsername('master');
$token = new UsernamePasswordToken($person, null, 'main', $person->getRoles());
$session->set('_security_main', serialize($token));
$session->save();
$client->getCookieJar()->set(new Cookie($session->getName(), $session->getId()));
return $client;
}
public function testView()
{
$client = $this->createAuthorizedClient();
$crawler = $client->request('GET', '/person/view');
$this->assertEquals(
200,
$client->getResponse()->getStatusCode()
);
}
希望它可以帮助您节省时间和精力;)
Hope it helps to save your time and nerves ;)
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