php:use"Mockery";模拟另一个静态方法中调用的静态方法 [英] php:use "Mockery" to mock a static method called in another static method

问题描述

我想模拟一个静态方法，该方法已在使用Mokcery的另一种方法中使用，如下所示:

I want to mock a static method which has been used in another method using Mokcery,Just as follows:

Class SomeClass
{
   public static function methodA()
   {
     .....;
     self::B();
   } 
   public static function methodB()
   {
     Do SomeThing
   }
}

如果我想模拟methodB并使用methodA，则模拟功能不起作用，只是因为methodB在methodA中使用，如下所示

if I want to mock methodB,and use methodA,the mock function doesn't work, just because methodB is used in methodA,just as below

 use Mockery as m;
   $mocktest = m::mock->('SomeClass[B]');
   $mocktest->shouldReceive('B')->andReturn("expectedResult");
   $mocktest->methodA();

上面的代码将导致methodB仍返回其原始结果，而不是'expectedResult'. 我希望方法A中使用的方法B被嘲笑，我该如何操作?

The code above will result in methodB still return it's original result rather than 'expectedResult'. I expect the methodB used in the methodA to be mocked,how could I operate?

推荐答案

您需要使用别名来模拟静态方法:

You need to use an alias to mock a static method:

$mock = \Mockery::mock('alias:SomeClass');

请注意，类尚未加载.否则嘲讽将无法对其进行别名.

Note that class can't be loaded yet. Otherwise mockery won't be able to alias it.

文档中的更多信息:

• 模拟公共静态方法
• 快速参考

• Mocking Public Static Methods
• Quick Reference

请注意，模拟静态方法不是一个好主意.如果您觉得自己需要它，则可以在设计上遇到问题. 对正在测试的班级进行模拟甚至更糟，这表明您的班级职责太多.

Just be warned that mocking static methods is not a good idea. If you feel like you need it you have problem with design. Mocking the class you're testing is even worse and indicates your class has too many responsibilities.

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