phpunit测试ExpectedException无法正常工作 [英] phpunit testing expectedException not working

问题描述

我正在尝试为InvalidArgumentException测试我的班级，但得到

I am trying to test my class for InvalidArgumentException but I get

Tests \ BarTest :: should_receive_parameter缺少参数1 Itdc \ Foo \ Bar :: __ construct()，在 第10行上的/mypath/foo/tests/BarTest.php和 定义

Tests\BarTest::should_receive_parameter Missing argument 1 for Itdc\Foo\Bar::__construct(), called in /mypath/foo/tests/BarTest.php on line 10 and defined

这是我使用的测试(BarTest.php)文件:

This is the test (BarTest.php) file I use:

<?php namespace Tests;
use Itdc\Foo\Bar;
class BarTest extends \PHPUnit_Framework_TestCase {
    /** @test */
    public function should_receive_parameter() {
        $this->setExpectedException('Exception');
        $id = new Bar;
    }
}

这是Bar类:

<?php namespace Itdc\Foo;
class Bar {
    public function __construct($a) {
        // do something
    }
}

我尝试在评论部分放入setExpectedException，也尝试使用InvalidArgumentException，但是没有运气.

I have tried to puth setExpectedException in comment section, also tried to use InvalidArgumentException, but no luck.

任何暗示我做错了事.

推荐答案

如果直接捕获它，则可以var_dump()异常.

If you catch it directly you can var_dump() the exception.

/** @test */
public function shouldThrowException() {
  try {
    new Foo();
  } catch (\Exception $e) {
    var_dump($e);
  }
}

输出:

class PHPUnit_Framework_Error_Warning#19 (9) {
  ...

因此，这里的源代码不会触发异常，而是会引发错误，PHPUnit会将错误转换为特定的异常.但是它没有包含在断言中.

So here the source does not trigger an exception but an error, PHPUnit converts the error into a specific exception. But it does not include it in the assertions.

尝试使用特定的异常名称:

Try using the specific exception name:

/** @test */
public function shouldThrowException() {
  $this->setExpectedException('PHPUnit_Framework_Error_Warning');
  new Foo();
}

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