根据SizeMode转换PictureBox选择矩形 [英] Convert PictureBox Selection Rectangle according to SizeMode

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本文介绍了根据SizeMode转换PictureBox选择矩形的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有两个PictureBoxes pbOriginal和pbFace.从pbOriginal中的图像中选择面部"后,我克隆矩形选择并将其放入pbFace中. 但是,由于pbOriginal使用的是SelectionMode=Stretch,因此实际复制的区域与所选区域不同.

如何转换矩形的坐标,以使其真正反映拉伸图像的坐标?

解决方案

下面是一个示例,它在绘制第一个矩形的同时向右绘制第二个矩形.

Point mDown = Point.Empty;
Point mCurr = Point.Empty;

private void pictureBox1_MouseDown(object sender, MouseEventArgs e)
{   mDown = e.Location;  }

private void pictureBox1_MouseMove(object sender, MouseEventArgs e)
{
    if (e.Button == System.Windows.Forms.MouseButtons.Left)
       { mCurr = e.Location; pictureBox1.Invalidate(); }
}

private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
    Rectangle r = new Rectangle(mDown.X, mDown.Y, mCurr.X - mDown.X, mCurr.Y - mDown.Y);
    e.Graphics.DrawRectangle(Pens.Orange, r);
    pictureBox2.Invalidate();
}

private void pictureBox2_Paint(object sender, PaintEventArgs e)
{
    if (pictureBox2.Image == null) return;

    float stretch1X = 1f * pictureBox1.Image.Width / pictureBox1.ClientSize.Width;
    float stretch1Y = 1f * pictureBox1.Image.Height / pictureBox1.ClientSize.Height;

    int x = (int)(mDown.X * stretch1X);
    int y = (int)(mDown.Y * stretch1Y);
    int x2 = (int)(mCurr.X * stretch1X);
    int y2 = (int)(mCurr.Y * stretch1Y);

    Rectangle r = new Rectangle(x, y, x2 - x, y2 - y);
    e.Graphics.DrawRectangle(Pens.Orange, r);
}

请注意,它假定您是从左上角到右下角绘制..

如果您要复制选择,则可以使用与DrawImage调用来源相同的因子和相同的Rectangle:

float stretch1X = 1f * pictureBox1.Image.Width / pictureBox1.ClientSize.Width;
float stretch1Y = 1f * pictureBox1.Image.Height / pictureBox1.ClientSize.Height;

Point pt = new Point((int)(mDown.X * stretch1X), (int)(mDown.Y * stretch1Y));
Size sz = new Size((int)((mCurr.X - mDown.X) * stretch1X), 
                   (int)((mCurr.Y - mDown.Y) * stretch1Y));


Rectangle rSrc = new Rectangle(pt, sz);
Rectangle rDest= new Rectangle(Point.Empty, sz);

Bitmap bmp = new Bitmap(sz.Width, sz.Height);
using (Graphics G = Graphics.FromImage(bmp))
    G.DrawImage(pictureBox1.Image, rDest, rSrc , GraphicsUnit.Pixel);
pictureBox2.Image = bmp;

您可能想对MouseUp事件进行编码以存储finla mCurr位置并触发复制..

I have two PictureBoxes pbOriginal and pbFace. After Selecting a "face" from an image in pbOriginal I clone the rectangle selection and place it into pbFace. However, Because pbOriginal is using SelectionMode=Stretch the actual area being copied is not the same as the area being selected.

How do I convert the coordinates of the Rectangle so that they truly reflect the coordinates of the Stretched Image?

解决方案

Here is an example that draws the second rectangle right along as you draw the first one..:

Point mDown = Point.Empty;
Point mCurr = Point.Empty;

private void pictureBox1_MouseDown(object sender, MouseEventArgs e)
{   mDown = e.Location;  }

private void pictureBox1_MouseMove(object sender, MouseEventArgs e)
{
    if (e.Button == System.Windows.Forms.MouseButtons.Left)
       { mCurr = e.Location; pictureBox1.Invalidate(); }
}

private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
    Rectangle r = new Rectangle(mDown.X, mDown.Y, mCurr.X - mDown.X, mCurr.Y - mDown.Y);
    e.Graphics.DrawRectangle(Pens.Orange, r);
    pictureBox2.Invalidate();
}

private void pictureBox2_Paint(object sender, PaintEventArgs e)
{
    if (pictureBox2.Image == null) return;

    float stretch1X = 1f * pictureBox1.Image.Width / pictureBox1.ClientSize.Width;
    float stretch1Y = 1f * pictureBox1.Image.Height / pictureBox1.ClientSize.Height;

    int x = (int)(mDown.X * stretch1X);
    int y = (int)(mDown.Y * stretch1Y);
    int x2 = (int)(mCurr.X * stretch1X);
    int y2 = (int)(mCurr.Y * stretch1Y);

    Rectangle r = new Rectangle(x, y, x2 - x, y2 - y);
    e.Graphics.DrawRectangle(Pens.Orange, r);
}

Note that it assumes that you are drawing top-left to bottom-right..

If you want to copy the selection you can use the same factors and the same Rectangle as the source for a DrawImage call:

float stretch1X = 1f * pictureBox1.Image.Width / pictureBox1.ClientSize.Width;
float stretch1Y = 1f * pictureBox1.Image.Height / pictureBox1.ClientSize.Height;

Point pt = new Point((int)(mDown.X * stretch1X), (int)(mDown.Y * stretch1Y));
Size sz = new Size((int)((mCurr.X - mDown.X) * stretch1X), 
                   (int)((mCurr.Y - mDown.Y) * stretch1Y));


Rectangle rSrc = new Rectangle(pt, sz);
Rectangle rDest= new Rectangle(Point.Empty, sz);

Bitmap bmp = new Bitmap(sz.Width, sz.Height);
using (Graphics G = Graphics.FromImage(bmp))
    G.DrawImage(pictureBox1.Image, rDest, rSrc , GraphicsUnit.Pixel);
pictureBox2.Image = bmp;

You may want to code the MouseUp event to store the finla mCurr position and trgger the copying..

这篇关于根据SizeMode转换PictureBox选择矩形的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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