PIL图像模式我是灰度的吗? [英] PIL Image mode I is grayscale?

问题描述

我正在尝试以整数格式而不是(R，G，B)格式指定图像的颜色.我假设必须根据"

I'm trying to specify the colours of my image in Integer format instead of (R,G,B) format. I assumed that I had to create an image in mode "I" since according to the documentation:

图像的模式定义了像素的类型和深度 图像.当前版本支持以下标准模式:

The mode of an image defines the type and depth of a pixel in the image. The current release supports the following standard modes:

• 1(1位像素，黑白，每字节存储一个像素)
• L(8位像素，黑白)
• P(8位像素，使用调色板映射到任何其他模式)
• RGB(3x8位像素，真彩色)
• RGBA(4x8位像素，带透明蒙版的真彩色)
• CMYK(4x8位像素，分色)
• YCbCr(3x8位像素，彩色视频格式)
• I(32位有符号整数像素)
• F(32位浮点像素)

• 1 (1-bit pixels, black and white, stored with one pixel per byte)
• L (8-bit pixels, black and white)
• P (8-bit pixels, mapped to any other mode using a colour palette)
• RGB (3x8-bit pixels, true colour)
• RGBA (4x8-bit pixels, true colour with transparency mask)
• CMYK (4x8-bit pixels, colour separation)
• YCbCr (3x8-bit pixels, colour video format)
• I (32-bit signed integer pixels)
• F (32-bit floating point pixels)

但是，这似乎是灰度图像.这是预期的吗?有没有一种方法可以基于32位整数指定彩色图像?在我的MWE中，我什至让PIL决定如何将红色"转换为"I"格式.

However this seems to be a grayscale image. Is this expected? Is there a way of specifying a coloured image based on a 32-bit integer? In my MWE I even let PIL decide how to convert "red" to the "I" format.

from PIL import Image

ImgRGB=Image.new('RGB', (200,200),"red") # create a new blank image
ImgI=Image.new('I', (200,200),"red") # create a new blank image
ImgRGB.show()
ImgI.show()

推荐答案

有没有一种方法可以基于32位整数指定彩色图像?

Is there a way of specifying a coloured image based on a 32-bit integer?

是的，为此使用RGB格式，但是使用整数而不是"red"作为颜色参数:

Yes, use the RGB format for that, but instead use an integer instead of "red" as the color argument:

from PIL import Image

r, g, b = 255, 240, 227
intcolor = (b << 16 ) | (g << 8 ) | r                                       
print intcolor # 14938367
ImgRGB = Image.new("RGB", (200, 200), intcolor)
ImgRGB.show()

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