如何获得已安装的脚本以忽略PYTHONPATH [英] How do I get an installed script to ignore PYTHONPATH

问题描述

我知道，如果我使用-E标志启动它，我可以让Python忽略PYTHONPATH.

I know I can get Python to ignore PYTHONPATH if I start it with the -E flag.

但是如何获得pip安装的脚本以具有此标志?

But how do I get a script installed by pip to have this flag?

我尝试了代码的脚本"和"console_scripts"部分，并且pip如果将它放在#上，则将-E剥离！线.

I tried both the "scripts" and the "console_scripts" section of the code and pip strips the -E if I put it on the #! line.

推荐答案

目前最简单的方法似乎是编写一个脚本，如果不包含该标志，它将重新启动Python:

The easiest way right now seems to be to put write a scripts that restarts Python if the flag is not included:

#!/bin/env python
import sys
if not sys.flags.ignore_environment:
      import os
      os.execv(sys.executable, [sys.executable, '-E'] + sys.argv)
# Run your actual script here

然后在setup.py中，输入以下内容:

Then in setup.py, put this:

setup(..., scripts=['myscript'], ...)

请勿使用entry_points/console_scripts.不应将其用于公共模块，而仅用于内部脚本.

Don't use entry_points/console_scripts. This should not be used for public modules, just for internal scripts.

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