命令的管道结果作为参数 [英] Piping result of command as an argument

问题描述

我想获得rpm -qa | grep something的结果，然后运行得到rpm -ql result-i-got的结果，并且全部一行.

I want to get the result of rpm -qa | grep something and then run the result I got rpm -ql result-i-got, and all in one line.

我发现这可行:

rpm -ql $(rpm -qa | grep something)

我想知道，是否有更好或什至不同的方式来传递此结果以获得与我上面所写内容相同的结果? 谢谢.

I wonder, is there any better or even different way of piping this result to get the same result of what I wrote above? Thanks.

推荐答案

xargs为此:

rpm -qa | grep something | xargs rpm -ql

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