VBA-测试值是否是PivotField的有效选择 [英] VBA - test if a value is a valid selection for a PivotField

问题描述

对于Sheet1上的数据透视表(pt1)，我使用VBA通过以下代码更改过滤器字段(filterfield)的值.假设field的值可以是A，B或C

For a pivot table (pt1) on Sheet1, I use VBA to change the value of a filter field (filterfield) using the code below. Let's say values for field can be A, B or C

Sheets("Sheet1").PivotTables("pt1").PivotFields("filterfield").CurrentPage = "A"

有时，就此问题而言，假设为randomonly，A，B或C将不是filterfield的有效选择.当VBA尝试更改该字段时，它将引发运行时错误.我想避免这种情况.

Occasionally, and let's say randomonly for the purposes of this question, A, B or C will not be a valid selection for filterfield. When VBA attempts to change the field, it throws a run-time error. I want to avoid this.

在运行上面的代码之前，如何检查我的值对于filterfield是否有效?我想避免使用出错时"，并且VBA不具有try/catch功能.

How can I check if my values are valid for filterfield before I run the code above? I would like to avoid using On Error and VBA does not have try/catch functionality..

推荐答案

您可以遍历PivotItems并针对您的测试检查Name.

You can iterate through the PivotItems and check the Name against your test.

Sub CheckIfPivotFieldContainsItem()

    Dim pt As PivotTable
    Set pt = Sheet1.PivotTables(1)

    Dim test_val As Variant
    test_val = "59"

    Dim pivot_item As PivotItem
    For Each pivot_item In pt.PivotFields("C").PivotItems
        If pivot_item.Name = test_val Then
            Debug.Print "MATCHES"
        End If
    Next pi

End Sub

相关数据表明匹配项应该存在，并且确实返回了MATCHES.

Relevant data shows that a match should exist and indeed it returns MATCHES.

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