sbt:子项目的动态聚合 [英] sbt: dynamic aggregation of subproject

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问题描述

我想发明一种系统,动态发现子项目,并将其自动汇总到我的项目中.或至少以某种方式进行配置.

I would like to invent a system to dynamically discover subprojects and aggregate them into my project automatically. Or at least configure this somehow.

为此,我计划有一个模块"文件夹或一个可选的配置文件,其中包含模块的路径.

To do this, I'm planning to have either a "modules" folder or an optional configuration file containing paths to the modules.

无论如何,我都需要遍历子文件夹(或遍历配置文件中的路径列表),并汇总每个子项目.我不知道该怎么办.

In any case I'd need to loop through subfolders (or loop through a list of paths from a configuration file), and aggregate each subproject. I don't know how to do that.

当前,我正在使用build.sbt文件在Play框架中进行构建.我需要像这样添加循环:

Currently I'm building in the Play framework with the build.sbt file. I would need to add the loop like this:

name := "mysite"
version := "1.0"
scalaVersion := "2.11.1"
lazy val root = (project in file(".")).enablePlugins(PlayJava)
//pseudocode:
foreach( folder in the 'modules' folder) { 
  lazy val module = (project in file(folder)).enablePlugins(PlayJava)
  root = root.dependsOn(module).aggregate(module)
}

有没有办法做到这一点?

Is there a way to do this?

这里的代码几乎可以正常工作:

EDIT 3: The code here is almost working:

object MyBuild extends Build {
  name := "mysite"
  version := "1.0"
  scalaVersion := "2.11.6"

  var m = new File("modules")
  var list = Seq[ProjectReference]()
  var deps = Seq[ClasspathDependency]()
  if (m.exists) {
    val subs = m.listFiles.filter ( _.isDirectory ).foreach { folder =>
      var modulePath = new File("modules", folder.getName)
      println("Found module " + modulePath)
      lazy val module:ProjectRef = ProjectRef(modulePath,folder.getName)
      lazy val dep:ClasspathDependency = ClasspathDependency(module, None)
      list = list :+ module
      deps = deps :+ dep
    }
  }

  lazy val root = Project(id = "mysite", base = file(".")).enablePlugins(PlayJava).aggregate(list:_*).dependsOn(deps:_*)
}

请参阅下面的Dale Wijnand解决方案.

See Dale Wijnand's solution below.

关于错误:RuntimeException: No project 'myModule' in 'file:/Users/me/mysite/modules/myModule'.我使用 https://stackoverflow.com/a/28820578

推荐答案

此处:

project/Build.scala

import sbt._
import sbt.Keys._

import play.sbt._
import play.sbt.Play.autoImport._

object Build extends Build {
  val commonSettings: Seq[Setting[_]] = Seq(
    scalaVersion := "2.11.7"
  )

  lazy val modules = (file("modules") * DirectoryFilter).get.map { dir =>
    Project(dir.getName, dir).enablePlugins(PlayJava).settings(commonSettings: _*)
  }

  lazy val root = (project in file("."))
    .enablePlugins(PlayJava)
    .settings(
      name := "mysite",
      version := "1.0"
    )
    .settings(commonSettings: _*)
    .dependsOn(modules map (m => m: ClasspathDependency): _*)
    .aggregate(modules map (m => m: ProjectReference): _*)

  override lazy val projects = root +: modules
}

注意,请确保模块目录中也没有包含将它们定义为项目的build.sbt文件,因为这将导致混淆的RuntimeException: No project 'x' in 'file:/x'类型异常,请参见

Note, make sure that the module directories don't also contain build.sbt files defining them as projects as that will cause confusing RuntimeException: No project 'x' in 'file:/x' type exception, see Can't use sbt 0.13.7 with Play subprojects

这篇关于sbt:子项目的动态聚合的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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