Scala如何将Map转换为元组的varargs? [英] Scala how to convert Map to varargs of tuples?

问题描述

在Scala Play 2.2.x测试中，我有一个Map[String, String]，我需要将其传递给接受(String, String)*的函数，即(String, String)元组的varargs.

In the context of Scala Play 2.2.x testing I have a Map[String, String] which I need to pass to a function that accepts (String, String)* i.e. a varargs of (String, String) tuple.

例如

val data : Map[String, String] = Map("value" -> "25", "id" -> "", "columnName" -> "trades")
route(FakeRequest(POST, "/whatever/do").withFormUrlEncodedBody(data))

但这会导致类型不匹配，因为withFormUrlEncodedBody仅接受(String, String)*类型.

but this gives a type mismatch because withFormUrlEncodedBody accepts only a (String, String)* type.

推荐答案

简单地:

def foo(names: (String, String)*) = names.foreach(println)
val folks = Map("john" -> "smith", "queen" -> "mary")
foo(folks.toSeq:_*)
// (john,smith)
// (queen,mary)

_* 向编译器提示的地方

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