Play Framework 2.1:Scala:如何获取整个基本URL(包括协议)? [英] Play Framework 2.1: Scala: how to get the whole base url (including protocol)?

问题描述

目前，我可以从请求，其中包括域和可选端口.不幸的是，它不包含协议(http vs https)，因此我无法为网站本身创建绝对URL.

Currently I am able to get the host from the request, which includes domain and optional port. Unfortunately, it does not include the protocol (http vs https), so I cannot create absolute urls to the site itself.

object Application extends Controller {
  def index = Action { request =>
    Ok(request.host + "/some/path") // Returns "localhost:9000/some/path"
  }
}

有什么方法可以从请求对象中获取协议吗?

Is there any way to get the protocol from the request object?

推荐答案

实际上，您的端口号是http还是https.

Actually your portnumber will give you if it's http or https.

通过https支持JAVA_OPTS=-Dhttps.port=9001 play start

这是一个代码段(您可以使用正则表达式使验证更加稳定，从属性中获取https端口号...)

Here's a code snippet (you can make the validation more stable with a regex, take the https port number from properties ...)

def path = Action { request =>
    val path = 
      if(request.host.contains(":9000"))
        "http://" + request.host + "/some/path"
      else
        "https://" + request.host + "/some/path"
    Ok(path)
  }

代码将返回

http://ServerIp:9000/some/path if it's thru http
https://ServerIp:9001/some/path if it's thru https

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