从PostgreSQL中的函数返回表类型 [英] Return Table Type from A function in PostgreSQL

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问题描述

我有一个函数,该函数的返回类型为TABLE,我想将表中的某些列转换为该RETURN TABLE类型的功能.当我执行该函数时,尽管它应该根据我的条件返回一些记录,但它没有给出错误但没有返回记录. 以下是我编写的代码,有人可以让我知道我哪里出错了吗?

I have a function from which has a return type as TABLE, and I want to get certain columns from my table into that RETURN TABLE type for my functionality. When I execute the function, it gives no error but returns no records although it should return some records based on the condition that I have. Below is the code that I have written, can someone let me know where have I gone wrong?

CREATE OR REPLACE FUNCTION ccdb.fn_email_details_auto()
  RETURNS TABLE (code integer, area smallint, action smallint, flag smallint, ucount  integer, view_cnt integer) AS
$BODY$

DECLARE 
sec_col refcursor;
cnt integer;
sec_code ccdb.update_qtable%ROWTYPE;

BEGIN

SELECT COUNT(DISTINCT section_code)
INTO cnt
FROM ccdb.update_qtable
WHERE entry_time::date = now()::date - interval '1 day';

OPEN sec_col FOR
    SELECT * FROM ccdb.update_qtable WHERE entry_time::date = now()::date - interval '1 day';

FOR i IN 1..cnt
LOOP

FETCH sec_col INTO sec_code;

    PERFORM section_code, ddu_area, ddu_action, status_flag, ccdb_ucount, ccdb_view_cnt
FROM ccdb.update_qtable
WHERE entry_time::date = now()::date - interval '1 day' AND section_code =  sec_code.section_code
ORDER BY ddu_area, ddu_action;

END LOOP;

CLOSE sec_col;

END;
$BODY$
  LANGUAGE plpgsql VOLATILE
  COST 100;

推荐答案

您的函数正在做很多的空工作.

Your function is doing a lot of empty work.

您可以使用 FOR循环进行隐式简化游标,而不是更繁琐和昂贵的显式游标.
仔细观察发现,您根本不需要任何这些.通过一个简单的查询彻底简化.我将其包装到一个SQL函数中:

You could simplify with a FOR loop with implicit cursor instead of the more tedious and expensive explicit cursor.
On a closer look it turns out you don't need any of this at all. Radically simplify with a simple query. I wrapped it into an SQL function:

CREATE OR REPLACE FUNCTION ccdb.fn_email_details_auto()
  RETURNS TABLE (code integer, area smallint, action smallint, flag smallint
               , ucount integer, view_cnt integer) AS
$func$

SELECT u.section_code, u.ddu_area, u.ddu_action, u.status_flag
     , u.ccdb_ucount, u.ccdb_view_cnt
FROM   ccdb.update_qtable u
WHERE  u.entry_time >= now()::date - 1
AND    u.entry_time <  now()::date        -- sargable!
ORDER  BY u.section_code, u.ddu_area, u.ddu_action;

$func$  LANGUAGE sql;

在返回相同代码的同时应该更快 .
另外,使用此:

Should be much faster while returning the same.
Also, use this:

WHERE  u.entry_time >= now()::date - 1
AND    u.entry_time <  now()::date

代替:

WHERE entry_time::date = now()::date - interval '1 day'

替代方法是可精,并且可以在entry_time上使用普通索引,该索引应对性能至关重要.

The alternative is sargable and can use a plain index on entry_time, which should be crucial for performance.

这篇关于从PostgreSQL中的函数返回表类型的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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