使用查询在PostgreSQL中设置列类型 [英] Using query to set the column type in PostgreSQL
问题描述
优秀的答案通过Alexandre GUIDET,我尝试运行以下查询:
After the excellent answer by Alexandre GUIDET, I attempted to run the following query:
create table egg (id (SELECT
pg_catalog.format_type(a.atttypid, a.atttypmod) as Datatype
FROM
pg_catalog.pg_attribute a
WHERE
a.attnum > 0
AND NOT a.attisdropped
AND a.attrelid = (
SELECT c.oid
FROM pg_catalog.pg_class c
LEFT JOIN pg_catalog.pg_namespace n ON n.oid = c.relnamespace
WHERE c.relname ~ '^(TABLENAME)$'
AND pg_catalog.pg_table_is_visible(c.oid)
)
and a.attname = 'COLUMNNAME'));
但是,PostgreSQL抱怨语法不正确.具体来说,它说我不能写:create table egg (id (SELECT
.
有什么解决方法吗?我不能将查询结果转换为文本并将其重新用作查询吗?
PostgreSQL, however, complains about incorrect syntax. Specifically it says that I cannot write: create table egg (id (SELECT
.
Are there any workarounds? Can't I convert the result of a query to text and reuse it as a query?
推荐答案
有一种更简单的方法.
SELECT pg_typeof(col)::text FROM tbl LIMIT 1
唯一的前提是模板表至少包含一行.请参见pg_typeof()上的手册
Only precondition is that the template table holds at least one row. See the manual on pg_typeof()
正如Milen所写,您需要EXECUTE
这样的动态DDL语句.
一个更简单的DO
语句:
As Milen wrote, you need to EXECUTE
dynamic DDL statements like this.
A much simpler DO
statement:
DO $$BEGIN
EXECUTE 'CREATE TABLE egg (id '
|| (SELECT pg_typeof(col)::text FROM tbl LIMIT 1) || ')';
END$$;
或者,如果不确定模板表中是否包含任何行:
Or, if you are not sure the template table has any rows:
DO $$BEGIN
EXECUTE (
SELECT format('CREATE TABLE egg (id %s)'
, format_type(atttypid, atttypmod))
FROM pg_catalog.pg_attribute
WHERE attrelid = 'tbl'::regclass -- name of template table
AND attname = 'col' -- name of template column
AND attnum > 0 AND NOT attisdropped
);
END$$;
这些条件似乎是多余的,因为您要查找任何特定的列
These conditions seem redundant, since you look for a specific column any
format()
需要Postgres 9.1 +.
format()
requires Postgres 9.1+.
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