从SQL Server中的完整文件名获取最后一个文件夹和文件名 [英] Get last folder and file name from full filename in SQL Server

问题描述

在SQL Server 2012中，我有以下工作代码来提取文件名和最低的文件夹名.可以有任何级别的子文件夹-我只需要最里面的文件夹和文件名.为此，SQL Server中是否有一种更易于阅读的方法?

I have following working code to extract file name along with lowest folder name, in SQL Server 2012. There can be any level of sub folders – I need only the innermost folder and the file name. Is there a more easy to read approach in SQL Server for this?

预期结果

MySubFolder/MyFile_4.0_20170901031307_2697.zip

当前有效的SQL

DECLARE @FileName varchar(200) =  'D:\SourceFiles\MyFolder\MySubFolder\MyFile_4.0_20170901031307_2697.zip'
DECLARE @TotalRecords INT
DECLARE @SectionName VARCHAR(128)
DECLARE @FileOnly VARCHAR(128)

SET @FileName = REPLACE( @FileName, '/', '\')
DECLARE @xml xml = '<r><n>' + REPLACE( @FileName, '\', '</n><n>') + '</n></r>'

DECLARE @FoldersList TABLE(FId INT IDENTITY(1,1), FolderOrFileName VARCHAR(128))
INSERT INTO @FoldersList (FolderOrFileName)
SELECT n.value( '.', 'varchar(200)') 
FROM @xml.nodes('r/n') n(n)


SELECT @TotalRecords = COUNT(*) FROM @FoldersList
SELECT @SectionName = FolderOrFileName FROM @FoldersList WHERE Fid = (@TotalRecords - 1)
SELECT @FileOnly = FolderOrFileName FROM @FoldersList WHERE Fid = (@TotalRecords)

SELECT @SectionName+'/'+@FileOnly

推荐答案

您可以使用

DECLARE @FileName varchar(200) = 
  'D:\SourceFiles\MyFolder\MySubFolder\MyFile_4.0_20170901031307_2697.zip'

SELECT RIGHT(@FileName, CHARINDEX('\', FileNameRev, 1+ CHARINDEX('\', FileNameRev)) - 1) 
FROM (SELECT REVERSE('\' + @FileName)) V(FileNameRev)

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