将Swift字符串数组转换为C字符串数组指针 [英] Convert a Swift Array of String to a to a C string array pointer
问题描述
我正在使用Swift 3,我需要与C API进行交互,例如,C API接受以NULL终止的字符串列表.
I'm on Swift 3, and I need to interact with an C API, which accepts a NULL-terminated list of strings, for example
const char *cmd[] = {"name1", "value1", NULL};
command(cmd);
在Swift中,API的导入方式如下
In Swift, the API was imported like
func command(_ args: UnsafeMutablePointer<UnsafePointer<Int8>?>!)
使用类型转换或unsafeAddress(of:)
尝试了数百次后,我仍然无法完成这项工作.即使我传递通过编译的有效指针,它也会在运行时崩溃,提示无效的内存访问(在strlen函数处).也许是关于ARC的事情?
After trying hundreds of times using type casting or unsafeAddress(of:)
I still cannot get this work. Even though I pass a valid pointer that passed compilation, it crashes at runtime saying invalid memory access (at strlen function). Or maybe it's something about ARC?
let array = ["name1", "value1", nil]
// ???
// args: UnsafeMutablePointer<UnsafePointer<Int8>?>
command(args)
推荐答案
You can proceed similarly as in How to pass an array of Swift strings to a C function taking a char ** parameter. It is a bit different because of the different
const
-ness of the argument array, and because there is a terminating
nil
(which must not be passed to strdup()
).
这是应该如何工作的:
let array: [String?] = ["name1", "name2", nil]
// Create [UnsafePointer<Int8>]:
var cargs = array.map { $0.flatMap { UnsafePointer<Int8>(strdup($0)) } }
// Call C function:
let result = command(&cargs)
// Free the duplicated strings:
for ptr in cargs { free(UnsafeMutablePointer(mutating: ptr)) }
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