修改字符串时出现分段错误 [英] Segmentation fault when modifying a string

问题描述

此代码中出现分段错误错误，但不知道为什么?

I am getting segmentation fault error in this code, but don't know why?

#include <stdio.h>

int main(void)
{
    char *ptr = "Linux";
    *ptr = 'T';

    printf("\n [%s] \n", ptr);

    return 0;
}

推荐答案

ptr是一个指向字符串文字的指针，但是您无法修改字符串文字，请将其更改为:

ptr is a pointer that points to a string literal, but you can't modify a string literal, change it to:

char ptr[] = "Linux";

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