如何在c中的某个位置终止字符指针? [英] How to terminate a character pointer at a certain location in c?

问题描述

我正在尝试通过将null终止符设置为特定位置终止c中的字符指针.

I'm trying to terminate a character pointer in c, at a specific location by setting the null terminator to it.

例如，如果我有一个char指针

for examples if I have a char pointer

 char *hi="hello";

我希望通过将o设置为null来将其设置为"hell".

I want it to be "hell" by setting the o to null.

我已经尝试使用

strcpy(hi+4, "\0");

但是它不起作用.

推荐答案

"hello"是字符串文字，因此无法修改，在您的代码中，hi指向此类文字中的第一个元素.任何试图修改它指向的东西的尝试都是未定义的行为.

"hello" is a string literal so it cannot modified, and in your code, hi points to the first element in such a literal. Any attempt to modify the thing it points to is undefined behaviour.

但是，如果您创建自己的char数组，则可以随意插入一个空终止符.例如，

However, if you create your own char array, you can insert a null terminator at will. For example,

char hi[] = "hello"; // hi is array with {'h', 'e', 'l', 'l', 'o', '\0'}
hi[4] = '\0';

在这里，hi是您拥有的char的长度6数组，可以更改其内容.设置第5个元素后，它包含{'h', 'e', 'l', 'l', '\0', '\0'}，并且打印出来将产生hell.

Here, hi is a length 6 array of char which you own and whose contents you can modify. After setting the 5th element, it contains {'h', 'e', 'l', 'l', '\0', '\0'}, and printing it would yield hell.

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