在C中分配浮点指针 [英] Assigning Float Pointers in C

问题描述

我目前拥有的是一个简单的函数，该函数基本上只是在给定参数指针的情况下重新分配指针，但是我收到一条错误消息，说我正在使用未初始化的变量之一.这就是我所拥有的，并且错误被抛出在* x = * k;

What I currently have is a simple function that basically just reassigns pointers given the parameter pointer but I'm getting an error saying that I'm using one of the variables uninitialized. Here's what I have and the error is being thrown on the line *x = *k;

float * program(const int *k)
{
    float *x;
    *x = *k;
    return x;
}

这必须是一个非常简单的修复程序，但是我觉得我只是想念它.

This has got to be a really simple fix, but I feel like I'm just missing it.

推荐答案

以下是您的代码正在做的事情:

Here's what your code is doing:

float * program(const int *k)
{
    // declare a pointer to a float, but don't initialize it,
    // so it is not actually pointing anywhere specific yet.
    float *x; 
    // Put the value pointed at by k into the location pointed at by x
    // But wait - we don't know where x is pointing, so this is BAD!
    *x = *k;
    return x;
}

这就是为什么您的编译器抱怨的原因.

And that is why your compiler is complaining.

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