如何在C语言中将双精度数组传递给函数? [英] How to pass a double array to a function in C?

问题描述

我整天都在努力解决这个问题:

I have been trying to solve this problem the whole day:

如何将双精度数组传递给函数?

How do I pass a double array to a function?

这里是一个例子:

int matrix[5][2] = { {1,2}, {3,4}, {5,6}, {7,8}, {9,10} };

我希望将此矩阵传递给名为eval_matrix的函数

And I wish to pass this matrix to function named eval_matrix,

void eval_matrix(int ?) {
    ...
}

我不知道应该用什么代替?

I can't figure out what should be in place of ?

有人可以帮助我解决这个问题吗?

Can anyone help me with this problem?

我知道数组可以作为指针传递，但是双精度数组(或三重数组)呢?

I know that an array can be passed just as a pointer, but what about a double array (or triple array?)

感谢Boda Cydo.

Thanks, Boda Cydo.

推荐答案

要用作数组，编译器必须知道数组的内部步幅，所以要么是:

To be usable as an array the compiler has to know the inner stride of the array, so it's either:

void eval_matrix( int m[5][2] ) { ...

或:

void eval_matrix( int m[][2], size_t od ) { ... /* od is the outer dimension */

或者只是:

void eval_matrix( int* p, size_t od, size_t id ) { ... /* ditto */

在任何情况下，它都是语法糖-数组会衰减为指针.

In any case it's syntactic sugar - the array is decayed to a pointer.

在前两种情况下，您可以照常引用m[i][j]，但在第三种情况下必须手动偏移为p[i*id + j].

In first two cases you can reference array elements as usual m[i][j], but will have to offset manually in the third case as p[i*id + j].

这篇关于如何在C语言中将双精度数组传递给函数?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！