C中的指针初始化概念 [英] Pointer initialization concept in C

问题描述

为什么这是错误的?

char *p;   
*p='a';

这本书只说了-使用未初始化的指针. 请任何人解释这是怎么回事?

The book only says -use of uninitialized pointer. Please can any one explain how that is?

推荐答案

char *c; //a pointer variable is being declared 
*c='a';

您使用了解引用运算符来访问c所指向的变量的值，但指针变量c没有指向任何变量，这就是您遇到运行时问题的原因.

you used the dereferencing operator to access the value of the variable to which c points to but your pointer variable c is not pointing to any variable thats why you are having runtime issues.

char *c; //declaration of the pointer variable
char var; 
c=&var; //now the pointer variable c points to variable var.
*c='a'; //value of var is set to 'a' using pointer 
printf("%c",var); //will print 'a' to the console

希望这会有所帮助.

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