Swift 3:如何在Google地图中删除跟踪的折线 [英] Swift 3: How to remove the tracked polyline in Google map

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本文介绍了Swift 3:如何在Google地图中删除跟踪的折线的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我已经画出了折线,但是我并不是没有什么编码可以删除Google地图中的追踪折线. 我在下面尝试一些编码.

I have draw the polylines, but I don't no that what coding can remove the tracked polyline in the google map. I'm trying some coding in below.

这是行不通的.

var polyline = GMSPolyline()
   polyline.map = nil 


这可以删除跟踪的折线,但是当我创建了标记并点按它时,标记无法播种信息窗口.


this is working to remove tracked polyline, but when I'm maked the markers and tap it, marker can not sow the info window.

mapView.clear()

谢谢

推荐答案

解决方案:

  1. 创建折线:通过GoogleMapsAPIs教学折线
  2. 创建变量oldPolylineArr/oldPolyline类型GMSPolyline/GMSPolyline_Array
  3. 将折线存储到oldPolyline
  4. 删除折线
  1. create polyline: teaching polyline by GoogleMapsAPIs
  2. create variable oldPolylineArr/oldPolyline type GMSPolyline/GMSPolyline_Array
  3. store the polyline to the oldPolyline
  4. remove the polyline

样本编码:

//Step 1:
var mapView = GMSMapView()
let path = GMSMutablePath()
path.add(CLLocationCoordinate2D(latitude: 37.36, longitude: -122.0))
path.add(CLLocationCoordinate2D(latitude: 37.45, longitude: -122.0))
path.add(CLLocationCoordinate2D(latitude: 37.45, longitude: -122.2))
path.add(CLLocationCoordinate2D(latitude: 37.36, longitude: -122.2))
path.add(CLLocationCoordinate2D(latitude: 37.36, longitude: -122.0))
let rectangle = GMSPolyline(path: path)

//Step 2:
var oldPolylineArr = [GMSPolyline]()

数组

//Step 3:
oldPolyline.append(rectangle)

//Step 4:
for p in (0 ..< oldPolylineArr.count) {
    oldPolylineArr[p].map = nil
}

不是数组

//Step 3:
oldPolyline = polyline

//Step 4:
oldPolyline.map = nil

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