故事板:使用委托/协议方法消除Popover [英] Storyboard: Dismissing Popover using delegate/protocol method

问题描述

我已经阅读了吨的内容，尽管大多数内容似乎与非故事板方法有关，但我认为我已经拼凑并弄清楚了.但是，以下代码不会导致我的弹出窗口被关闭. Popover中的dismissPopoverButtonPressed按钮会执行，但委托中dismissPopover方法中的断点永远不会命中.非常感谢有人关注代码，以发现错误.

I've read tons of stuff on this and while most seems to be in regards to the non-storyboard approach, I thought I had pieced bits together and figured it out. However, the following code does not result in my popover being dismissed. The dismissPopoverButtonPressed button in the Popover executes but a breakpoint in the dismissPopover method in the delegate never hits. Would very much appreciate someone casting an eye over the code to spot mistakes.

谢谢

在下面，NewGameViewController包含一个UIButton.按下此按钮将弹出Popover Segue，并随后显示包含PopViewController UIView的弹出窗口.

In the following, NewGameViewController contains a UIButton. Pressing this results in the Popover Segue and subsequent display of the popover containing the PopViewController UIView.

NewGameViewController.h

#import "PopViewController.h"
@interface NewGameViewController: UIViewController <DismissPopoverDelegate>
{
    UIPopoverController *popover;
}

NewGameViewController.m

@implementation NewGameViewController
-(void)prepareForSegue:(UIStoryboardPopoverSegue *)segue sender:(id)sender
{
    if ([[segue identifier] isEqualToString:@"popoverSegue"])
    {
        popover = [(UIStoryboardPopoverSegue *)segue popoverController];
        // getting warning: Assigning to 'id<UIPopoverControllerDelegate>' from incompatible type 'NewGameViewController *const__strong'
        //popover.delegate = self;
    }
}

-(void)dismissPopover
{
    [popover dismissPopoverAnimated:YES];
}

PopViewController.h

@protocol DismissPopoverDelegate <NSObject>
-(void) dismissPopover;
@end

@interface PopViewController: UIViewController
{
    __unsafe_unretained id<DismissPopoverDelegate> delegate;
}

@property (nonatomic, assign) id<DismissPopoverDelegate> delegate;
-(IBAction)dismissPopoverButtonPressed:(id)sender;
@end

PopViewController.m

#import "NewGameViewController.h"
@implementation PopViewController
@synthesize delegate;
-(IBAction)dismissPopoverButtonPressed:(id)sender
{
    [self.delegate dismissPopover];
}

推荐答案

从情节提要segue链接到弹出控件时，segue的popoverController属性引用标准UIPopoverController.该控制器本身具有属性， contentViewController ，它表示在弹出窗口中实际显示的视图控制器，在您的情况下为PopViewController.

When linking to a popover controller from a storyboard segue, the popoverController property of the segue refers to a standard UIPopoverController. This controller itself has a property, contentViewController, which will represent the view controller that is actually being presented within the popover, in your case the PopViewController.

因此，当确实需要将自身设置为弹出窗口的 content 视图控制器的委托时，当前代码会将自身设置为弹出窗口控制器的委托.

So, your current code is setting itself as the delegate of the popover controller, when it really needs to be setting itself as the delegate of the popover's content view controller.

您仍然需要保留对popover控制器的引用以关闭它，因此保留您现有的代码，但要进行以下更改:

You still need to keep a reference to the popover controller around, to dismiss, so keep your existing code, but make the following change:

-(void)prepareForSegue:(UIStoryboardPopoverSegue *)segue sender:(id)sender
{
    if ([[segue identifier] isEqualToString:@"popoverSegue"])
    {
        popover = [(UIStoryboardPopoverSegue *)segue popoverController];
        // Get a reference to the content view controller of the popover
        PopViewController *popVC = (PopViewController*)popover.contentViewController;
        // Set ourselves as the content VC's delegate
        popVC.delegate = self;
    }
}

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