角<路由器出口名称="弹出>>更改URL路径结构? [英] Angular <router-outlet name="popup"> change URL path structure?

问题描述

我正在使用一个弹出窗口(请参阅文档): https://angular.io/guide/router #displaying-multipleroutes-in-named-outlets

I'm using a popup (refering to the docs): https://angular.io/guide/router#displaying-multiple-routes-in-named-outlets

除URL结构外，一切都很好:

Everything is fine apart from the URL structure:

/domain/subPath/(popup:myopoup)

/domain/subPath/(popup:myopoup)

如何用括号更改此默认结构? 我希望它如下:

How can I change this default structure with parenthesis? I would like it to be as follows:

/domain/subPath/popup

/domain/subPath/popup

换句话说，我想删除括号，包括URL内的冒号.

In other words, I want to remove the brackets including the colon inside the URL.

在他们的文档中，弹出窗口也以这种方式显示(带有括号)

Inside their documentation the popup also appears in that manner (with brackets)

这是一些代码:

.ts

{
  path: 'mypopup',
  component: MyComponent,
  outlet: 'popup'
},

.html

<a [routerLink]="[{ outlets: { popup: ['mypopup'] } }]">Contact</a>
<router-outlet name="popup"></router-outlet>

推荐答案

您可以使用URL序列化程序来更改url结构

you can use URL serializer, to change url structure

import { UrlTree ,DefaultUrlSerializer, UrlSerializer } from '@angular/router';

export class cleanUrlSerializer extends DefaultUrlSerializer {  
public parse(url: string): UrlTree {
    function cleanUrl(url) {
        return url.replace(/\(|\)/g,'') // for example to delete parenthesis
    }
    return super.parse(cleanUrl(url));
}
}

导入此类，并将其添加为模块中的提供者

import this class and add it as provider in your module

 providers: [
    {
        provide: UrlSerializer,
        useClass: cleanUrlSerializer 
    }
  ]

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