Chrome扩展程序开发:从background_html调用弹出窗口中的方法 [英] Chrome extension development: Call a method in popup from background_html

问题描述

我有一个名为mf_popup.html的弹出窗口，我的背景页面名为mf_background.html.

I have a popup named mf_popup.html and my background page is named mf_background.html.

启动浏览器时，背景页面会触发(据我所知，我是Chrome开发的新手)，我想从背景页面的mf_popup.html页面中调用一个函数.

As I start the browser my background page fires (as is my understanding, I am new to Chrome development), and I would like to call a function in my mf_popup.html page from my background page.

例如:

Start chrome

background page fires

background page calls some function in popup page (which initiates some stuff)

我该如何做?

推荐答案

，如果您将所需的代码放在mf_javascript.js的两个html文件中，并在此行中都包含脚本，则此行:

if you place the needed code in both html-files in mf_javascript.js and includes the script in both with this line:

<script type="text/javascript" src="mf_javascript.js">

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